Advertisements
Advertisements
प्रश्न
Find the area of a quadrilateral ABCD in which AD = 24 cm, ∠BAD = 90° and BCD forms an equilateral triangle whose each side is equal to 26 cm. (Take √3 = 1.73)
उत्तर
Given that, a quadrilateral ABCD in which AD = 24 cm, ∠BAD = 90°
BCD is equilateral triangle and sides BC = CD = BD = 26 cm
In ΔBAD By using Pythagoras theorem
`BA^2=BD^2-AD^2`
`⇒BA=sqrt(BD^2-AD^2)`
`=sqrt(676-576)`
`sqrt(100)=10cm`
𝐴𝑟𝑒𝑎 𝑜𝑓 Δ𝐵𝐴𝐷=`1/2`×𝐵𝐴×𝐴𝐷
=`1/2`×10×24
=`120cm^2`
𝐴𝑟𝑒𝑎 𝑜𝑓 Δ𝐵𝐶𝐷=`sqrt(a)/4xx(26)^2=292.37cm^2`
∴𝐴𝑟𝑒𝑎 𝑜𝑓 𝑞𝑢𝑎𝑑𝑟𝑖𝑙𝑎𝑡𝑒𝑟𝑎𝑙
ABCD = Area of ΔBAD + area of ΔBCD
= 120 + 292.37
= 412.37 `cm^2`
APPEARS IN
संबंधित प्रश्न
Radha made a picture of an aeroplane with coloured papers as shown in the given figure. Find the total area of the paper used.
Find the area of an equilateral triangle having each side 4 cm.
If each side of a equilateral triangle is tripled then what is the percentage increase in the area of the triangle?
The sides of a triangular field are 325 m, 300 m and 125 m. Its area is
The sides of a triangle are 11 cm, 15 cm and 16 cm. The altitude to the largest side is
The lengths of the sides of Δ ABC are consecutive integers. It Δ ABC has the same perimeter as an equilateral triangle with a side of length 9 cm, what is the length of the shortest side of ΔABC?
A land is in the shape of rhombus. The perimeter of the land is 160 m and one of the diagonal is 48 m. Find the area of the land.
The length of each side of an equilateral triangle having an area of `9sqrt(3)`cm2 is ______.
If the area of an equilateral triangle is `16sqrt(3)` cm2, then the perimeter of the triangle is ______.
In a triangle, the sides are given as 11 cm, 12 cm and 13 cm. The length of the altitude is 10.25 cm corresponding to the side having length 12 cm.
