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प्रश्न
Find the Cartesian equation of the following planes:
`vecr.(hati + hatj-hatk) = 2`
उत्तर
It is given that equation of the plane is
`vecr.(hati + hatj-hatk) = 2`
For any arbitrary point P (x, y, z) on the plane, position vector `vecr`is given by,
`vecr = xhati +yhatj-zhatk`
Substituting the value of `vecr` in equation (1), we obtain
`(xhati + yhatj - zhatk).(hati + hatj - hatk) = 2`
=> x + y - z = 2
This is the Cartesian equation of the plane.
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