Advertisements
Advertisements
प्रश्न
Find `"dy"/"dx"` of the following function:
x = log t, y = sin t
बेरीज
उत्तर
x = log t y = sin t
`"dx"/"dt" = 1/"t"` `"dy"/"dt"` = cos t
`"dy"/"dx" = ("dy"/"dt")/("dx"/"dt")`
`= (cos "t")/(1/"t")` = t cos t
shaalaa.com
Differentiation Techniques
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Differential Calculus - Exercise 5.8 [पृष्ठ १२२]
APPEARS IN
संबंधित प्रश्न
Differentiate the following with respect to x.
`(3 + 2x - x^2)/x`
Differentiate the following with respect to x.
`(x^2 + x + 1)/(x^2 - x + 1)`
Differentiate the following with respect to x.
ex (x + log x)
Differentiate the following with respect to x.
sin2 x
Differentiate the following with respect to x.
xsin x
If xm . yn = (x + y)m+n, then show that `"dy"/"dx" = y/x`
Find y2 for the following function:
y = e3x+2
Find y2 for the following function:
y = log x + ax
If y = 2 + log x, then show that xy2 + y1 = 0.
If xy2 = 1, then prove that `2 "dy"/"dx" + y^3`= 0
