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Find the equation of the right bisector of the line segment joining the points (a, b) and (a1, b1). - Mathematics

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प्रश्न

Find the equation of the right bisector of the line segment joining the points (a, b) and (a1, b1).

थोडक्यात उत्तर

उत्तर

Let A (a, b) and B (a1, b1) be the given points. Let C be the midpoint of AB.

\[\therefore\text {  Coordinates of C } = \left( \frac{a + a_1}{2}, \frac{b + b_1}{2} \right)\]

And, slope of AB = \[\frac{b_1 - b}{a_1 - a}\]

So, the slope of the right bisector of AB is \[- \frac{a_1 - a}{b_1 - b}\] 

Thus, the equation of the right bisector of the line segment joining the points (a, b) and (a1, b1) is

\[y - \frac{b + b_1}{2} = - \frac{a_1 - a}{b_1 - b}\left( x - \frac{a + a_1}{2} \right)\]

\[ \Rightarrow 2\left( a_1 - a \right)x + 2y\left( b_1 - b \right) + \left( a^2 + b^2 \right) - \left( {a_1}^2 + {b_1}^2 \right) = 0 \]

This is equation of the required line .

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पाठ 23: The straight lines - Exercise 23.12 [पृष्ठ ९३]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 23 The straight lines
Exercise 23.12 | Q 11 | पृष्ठ ९३

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