Advertisements
Advertisements
प्रश्न
Find the Factors of the Polynomial Given Below.
2x2 + x – 1
उत्तर
2x2 + x – 1
= 2x2 + 2x - x - 1 ...\[\begin{array}{cc}
\ce{2 ×-1=-2}\\
\phantom{..........}/\backslash\\
\phantom{...........}\ce{2}\phantom{..}\ce{-1}\phantom{}
\end{array}\]
= 2x (x + 1) - 1(x + 1)
= (x + 1) (2x - 1)
APPEARS IN
संबंधित प्रश्न
Factorise:
2x2 + 7x + 3
Factorise:
6x2 + 5x – 6
Determine the following polynomial has (x + 1) a factor:
x4 + 3x3 + 3x2 + x + 1
Factorize the following polynomial.
(x – 5)2 – (5x – 25) – 24
Which of the following is a factor of (x + y)3 – (x3 + y3)?
Determine which of the following polynomials has x – 2 a factor:
3x2 + 6x – 24
Show that p – 1 is a factor of p10 – 1 and also of p11 – 1.
Find the value of m so that 2x – 1 be a factor of 8x4 + 4x3 – 16x2 + 10x + m.
If x + 1 is a factor of ax3 + x2 – 2x + 4a – 9, find the value of a.
Factorise:
1 + 64x3
