Advertisements
Advertisements
प्रश्न
Find the Factors of the Polynomial Given Below.
2x2 + x – 1
उत्तर
2x2 + x – 1
= 2x2 + 2x - x - 1 ...\[\begin{array}{cc}
\ce{2 ×-1=-2}\\
\phantom{..........}/\backslash\\
\phantom{...........}\ce{2}\phantom{..}\ce{-1}\phantom{}
\end{array}\]
= 2x (x + 1) - 1(x + 1)
= (x + 1) (2x - 1)
APPEARS IN
संबंधित प्रश्न
Determine the following polynomial has (x + 1) a factor:
x3 + x2 + x + 1
Use the Factor Theorem to determine whether g(x) is a factor of p(x) in the following case:
p(x) = x3 + 3x2 + 3x + 1, g(x) = x + 2
Use the Factor Theorem to determine whether g(x) is a factor of p(x) in the following case:
p(x) = x3 − 4x2 + x + 6, g(x) = x − 3
Determine the following polynomial has (x + 1) a factor:
x4 + x3 + x2 + x + 1
Find the factor of the polynomial given below.
3y2 – 2y – 1
If x + 1 is a factor of the polynomial 2x2 + kx, then the value of k is ______.
x + 1 is a factor of the polynomial ______.
Show that p – 1 is a factor of p10 – 1 and also of p11 – 1.
If x + 1 is a factor of ax3 + x2 – 2x + 4a – 9, find the value of a.
Factorise:
1 + 64x3