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प्रश्न
Find the factor of the polynomial given below.
3y2 – 2y – 1
योग
उत्तर
3y2 – 2y – 1
= 3y2 – 3y + y – 1
= 3y (y – 1) + 1 (y – 1)
= (y – 1) (3y + 1)
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Factorisation of Polynomials
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अध्याय 3: Polynomials - Practice Set 3.6 [पृष्ठ ५४]
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