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प्रश्न
Find the median and mode for the set of numbers:
2, 2, 3, 5, 5, 5, 6, 8 and 9
उत्तर
Median = `(9 + 1)/2` = 5th term which is 5.
Mode = 5 because it occurs maximum number of times.
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संबंधित प्रश्न
Marks obtained by 40 students in a short assessment is given below, where a and b are two missing data.
| Marks | 5 | 6 | 7 | 8 | 9 |
| Number of Students | 6 | a | 16 | 13 | b |
If the mean of the distribution is 7.2, find a and b.
Find mean by step-deviation method:
| C.I. | 63 – 70 | 70 – 77 | 77 – 84 | 84 – 91 | 91 – 98 | 98 – 105 | 105 – 112 |
| Frequency | 9 | 13 | 27 | 38 | 32 | 16 | 15 |
Using the information given in the adjoining histogram, calculate the mean.
If the mean of the following observations is 54, find the value of p.
| Class | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 | 80 – 100 |
| Frequency | 7 | p | 10 | 9 | 13 |
Draw a histogram and hence estimate the mode for the following frequency distribution:
| Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 |
| Freq | 2 | 8 | 10 | 5 | 4 | 3 |
Following 10 observations are arranged in ascending order as follows.
2, 3, 5, 9, x + 1, x + 3, 14, 16, 19, 20
If the median of the data is 11, find the value of x.
The weights of 11 students in a class are 36 kg, 45 kg, 44 kg, 37 kg, 36 kg, 41 kg, 45 kg, 43 kg, 39 kg, 42 kg and 40 kg. Find the median of their weights.
A boy scored the following marks in various class tests during a term, each test being marked out of 20.
15, 17, 16, 7, 10, 12, 14, 16, 19, 12, 16
What is his median marks?
Find the median of the given data:
14, −3, 0, −2, −8, 13, −1, 7
In a given data, arranged in ascending or descending order, the middle most observation is called ______.
