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प्रश्न
Find the point to which the origin should be shifted after a translation of axes so that the following equation will have no first degree terms: x2 − 12x + 4 = 0
उत्तर
Let the origin be shifted to (h, k). Then, x = X + h and y = Y + k.
Substituting x = X + h and y = Y + k in the equation x2 − 12x + 4 = 0, we get:
\[\left( X + h \right)^2 - 12\left( X + h \right) + 4 = 0\]
\[ \Rightarrow X^2 + 2hX + h^2 - 12X - 12h + 4 = 0\]
\[ \Rightarrow X^2 + X\left( 2h - 12 \right) + h^2 - 12h + 4 = 0\]
For this equation to be free from the terms containing X and Y, we must have
Hence, the origin should be shifted to the point \[\left( 6, k \right), k \in R\].
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