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प्रश्न
Find the slope of a line passing through the given pair of points (3,7) and (5,13)
उत्तर
Slope of line = `("y"_2 - "y"_1)/("x"_2 - "x"_1)`
= `(13 - 7)/( 5 - 3)`
= 3
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संबंधित प्रश्न
Find the slope of the line parallel to AB if : A = (−2, 4) and B = (0, 6)
Find the slope of the line perpendicular to AB if : A = (3, −2) and B = (−1, 2)
Find the slope of a line passing through the points (x, 9) and (12, 6) is `(-1)/3 = ("y"_2 - "y"_1)/("x"_2 - "x"_1)`
Find the value of x so that the line passing through (3, 4) and (x, 5) makes an angle 135° with positive direction of X-axis.
Find the value, of k, if the line represented by kx – 5y + 4 = 0 and 4x – 2y + 5 = 0 are perpendicular to each other.
Given that (a, 2a) lies on line`(y)/(2) = 3 - 6`.Find the value of a.
If A(6, 1), B(8, 2), C(9, 4) and D(7, 3) are the vertices of `square`ABCD, show that `square`ABCD is a parallelogram.
Solution:
Slope of line = `("y"_2 - "y"_1)/("x"_2 - "x"_1)`
∴ Slope of line AB = `(2 - 1)/(8 - 6) = square` .......(i)
∴ Slope of line BC = `(4 - 2)/(9 - 8) = square` .....(ii)
∴ Slope of line CD = `(3 - 4)/(7 - 9) = square` .....(iii)
∴ Slope of line DA = `(3 - 1)/(7 - 6) = square` .....(iv)
∴ Slope of line AB = `square` ......[From (i) and (iii)]
∴ line AB || line CD
∴ Slope of line BC = `square` ......[From (ii) and (iv)]
∴ line BC || line DA
Both the pairs of opposite sides of the quadrilateral are parallel.
∴ `square`ABCD is a parallelogram.
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Slope of X-axis is ______.