Advertisements
Advertisements
प्रश्न
Find the co-ordinates of the focus, vertex, equation of the directrix, axis and the length of latus rectum of the parabola
x2 = - 16y
उत्तर
x2 = - 16y
x2 = - 4(4)y
∴ a = 4
| Vertex | (0, 0) | (0, 0) |
| Focus | (0, -a) | (0, -4) |
| Axis | y-axis | x = 0 |
| Directrix | y - a = 0 | y - 4 = 0 |
| Length of Latus rectum | 4a | 16 |
APPEARS IN
संबंधित प्रश्न
Find the vertex, focus, axis, directrix, and the length of the latus rectum of the parabola y2 – 8y – 8x + 24 = 0.
The focus of the parabola x2 = 16y is:
The distance between directrix and focus of a parabola y2 = 4ax is:
Find the equation of the ellipse in the cases given below:
Length of latus rectum 4, distance between foci `4sqrt(2)`, centre (0, 0) and major axis as y-axis
Find the equation of the hyperbola in the cases given below:
Foci (± 2, 0), Eccentricity = `3/2`
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
`x^2/25 - y^2/144` = 1
Prove that the length of the latus rectum of the hyperbola `x^2/"a"^2 - y^2/"b"^2` = 1 is `(2"b"^2)/"a"`
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
`(x + 1)^2/100 + (y - 2)^2/64` = 1
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
`(y - 2)^3/25 + (x + 1)^2/16` = 1
Choose the correct alternative:
If x + y = k is a normal to the parabola y2 = 12x, then the value of k is 14
