Advertisements
Advertisements
प्रश्न
Find the co-ordinates of the focus, vertex, equation of the directrix, axis and the length of latus rectum of the parabola
y2 = 20x
उत्तर
y2 = 20x
y2 = 4(5)x
∴ a = 5
Vertex | (0, 0) | (0, 0) |
Focus | (a, 0) | (5, 0) |
Axis | x-axis | y = 0 |
Directrix | x + a = 0 | x + 5 = 0 |
Length of Latus rectum | 4a | 20 |
APPEARS IN
संबंधित प्रश्न
Find the equation of the parabola which is symmetrical about x-axis and passing through (–2, –3).
The double ordinate passing through the focus is:
The distance between directrix and focus of a parabola y2 = 4ax is:
The equation of directrix of the parabola y2 = -x is:
Find the equation of the ellipse in the cases given below:
Length of latus rectum 8, eccentricity = `3/5` centre (0, 0) and major axis on x-axis
Find the equation of the hyperbola in the cases given below:
Centre (2, 1), one of the foci (8, 1) and corresponding directrix x = 4
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
`x^2/25 - y^2/144` = 1
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
9x2 – y2 – 36x – 6y + 18 = 0
Choose the correct alternative:
The eccentricity of the hyperbola whose latus rectum is 8 and conjugate axis is equal to half the distance between the foci is
Choose the correct alternative:
If x + y = k is a normal to the parabola y2 = 12x, then the value of k is 14