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Find the equation of the parabola which is symmetrical about x-axis and passing through (–2, –3). - Business Mathematics and Statistics

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प्रश्न

Find the equation of the parabola which is symmetrical about x-axis and passing through (–2, –3).

बेरीज

उत्तर

Equation of the parabola symmetrical about X-axis is either y2 = 4ax or y2 = - 4ax.

Since the parabola passes through (-2, -3) it will be of the form y2 = - 4ax   ...(1)

Substituting (-2, -3) in (1) we get, 

y2 = - 4ax

(-3)2 = - 4a(-2)

⇒ 9 = 8a

⇒ a = `9/8`

Substituting a = `9/8` in (1) we get,

y2 = - 4ax

y2 = - 4`(9/8)`x

⇒ y2 = `(-9)/2`x

which is required equation of the parabola.

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पाठ 3: Analytical Geometry - Miscellaneous Problems [पृष्ठ ७३]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 11 TN Board
पाठ 3 Analytical Geometry
Miscellaneous Problems | Q 9 | पृष्ठ ७३
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