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प्रश्न
Find the equation of the line whose slope is `-4/3` and which passes through (−3, 4).
उत्तर
Given, slope = `-4/3`
The equation passes through (−3, 4) = (x1, y1)
Substituting the values in y – y1 = m (x − x1), we get,
`y - 4 = -4/3(x + 3)`
3y – 12 = −4x – 12
4x + 3y = 0, which is the required equation.
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