Question

Find the equation of the line whose slope is ${\displaystyle -\frac{4}{3}}$ and which passes through (−3, 4).

Answer 1

Given, slope = ${\displaystyle -\frac{4}{3}}$

The equation passes through (−3, 4) = (x₁, y₁)

Substituting the values in y – y₁ = m (x − x₁), we get,

${\displaystyle y-4=-\frac{4}{3}(x+3)}$

3y – 12 = −4x – 12

4x + 3y = 0, which is the required equation.