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Question
Find the equation of a line which passes through (5, 4) and makes an angle of 60° with the positive direction of the x-axis.
Solution
Slope of the line = tan 60° = `sqrt(3)`
The line passes through the point (5, 4) = (x1, y1)
Substituting the values in y – y1 = m (x – x1), we get,
`y - 4 = sqrt(3)(x - 5)`
`y - 4 = sqrt(3)x - 5sqrt(3)`
`y = sqrt(3)x + 4 - 5sqrt(3)`, which is the required equation.
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