Advertisements
Advertisements
प्रश्न
Find the measure of each interior angle of a regular polygon of: 10 sides
उत्तर
When n = 10
∴ Each interior angle of a regular polygon
= `(("n" - 2) xx 180°)/"n"`
= `((10 - 2) xx 180°)/(10)`
= 144°.
APPEARS IN
संबंधित प्रश्न
The angles of a pentagon are in the ratio 4: 8: 6: 4: 5.
Find each angle of the pentagon.
One angle of a six-sided polygon is 140o and the other angles are equal.
Find the measure of each equal angle.
The ratio between an exterior angle and an interior angle of a regular polygon is 2 : 3. Find the number of sides in the polygon.
Find the measure of each interior angle of a regular polygon of: 15 sides
Find the number of sides in a regular polygon, when each interior angle is: 135°
Is it possible to have a polygon whose each interior angle is 105°?
The ratio between the number of sides of two regular polygon is 3 : 4 and the ratio between their interior angles is 2 : 3. Find the number of sides of each polygon.
Find the value of each angle of a heptagon If three of its angles measure 132° each and the remaining four.
In a pentagon PQRST, ∠P = 100°, ∠Q = 120° and ∠S = ∠T. The sides PQ and SR, when produced meet at right angle. Find ∠QRS and ∠PTS.
In a regular pentagon PQRST, PR = QT intersect at N. Find the angle RQT and QNP.