Advertisements
Advertisements
प्रश्न
Find the measure of each interior angle of a regular polygon of: 15 sides
उत्तर
When n = 15
∴ Each interior angle of a regular polygon
= `(("n" - 2) xx 180°)/"n"`
= `((15 - 2) xx 180°)/(15)`
= 156°.
APPEARS IN
संबंधित प्रश्न
The angles of a pentagon are in the ratio 4: 8: 6: 4: 5.
Find each angle of the pentagon.
In a polygon, there are 5 right angles and the remaining angles are equal to 195o each. Find the number of sides in the polygon.
Two angles of an eight-sided polygon are 142o and 176o. If the remaining angles are equal to each other; find the magnitude of each of the equal angles.
Find each exterior angle of a regular polygon of: 9 sides
Find each exterior angle of a regular polygon of: 15 sides
The number of sides of two regular polygons are in the ratio 2 : 3 and their interior angles are in the ratio 9 : 10. Find the number of sides of each polygon.
KL, LM and MN are three consecutive sides of a regular polygon. If ∠LKM = 20°, find the interior angle of the polygon and the number of sides of the polygon.
The number angle of a regular polygon is double the exterior angle. Find the number of sides of the polygon.
In a regular pentagon PQRST, PR = QT intersect at N. Find the angle RQT and QNP.
Each interior angle of a regular polygon is 162°. Another regular polygon has number of sides double the first polygon. Find each interior angle of the second polygon.
