Advertisements
Advertisements
Question
Find the measure of each interior angle of a regular polygon of: 10 sides
Solution
When n = 10
∴ Each interior angle of a regular polygon
= `(("n" - 2) xx 180°)/"n"`
= `((10 - 2) xx 180°)/(10)`
= 144°.
APPEARS IN
RELATED QUESTIONS
The angles of a pentagon are in the ratio 4: 8: 6: 4: 5.
Find each angle of the pentagon.
In a polygon, there are 5 right angles and the remaining angles are equal to 195o each. Find the number of sides in the polygon.
Find the sum of the interior angles of a polygon of: 7 sides
Find each exterior angle of a regular polygon of: 15 sides
Is it possible to have a polygon whose sum of interior angles is 7 right angles?
A heptagon has three angles equal to 120°, and the other four angles are equal. Find all the angles.
In a polygon, there are 3 right angles and the remaining angles are equal to 165°. Find the number of sides in the polygon.
If the difference between an exterior angle of a regular polygon of 'n' sides and an exterior angle of another regular polygon of '(n + 1)' sides is equal to 4°; find the value of 'n'.
Find the value of each angle of a heptagon If three of its angles measure 132° each and the remaining four.
In a regular pentagon PQRST, PR = QT intersect at N. Find the angle RQT and QNP.
