Advertisements
Advertisements
Question
The angles of a pentagon are in the ratio 4: 8: 6: 4: 5.
Find each angle of the pentagon.
Solution
Let the angles of the pentagon are 4x, 8x, 6x, 4x and 5x.
Thus we can write
4x + 8x+ 6x + 4x +5x = 540°
27x =540°
x = 20°
Hence the angles of the pentagon are:
4 × 20° = 80° ,
8 × 20°= 160° ,
6 × 20°= 120° ,
4 × 20°= 80° ,
5 × 20°= 100°
APPEARS IN
RELATED QUESTIONS
The difference between an exterior angle of (n - 1) sided regular polygon and an exterior angle of (n + 2) sided regular polygon is 6° find the value of n.
In a parallelogram ABCD, AB = 20 cm and AD = 12 cm. The bisector of angle A meets DC at E and BC produced at F.
Find the length of CF.
Find the sum of the interior angles of a polygon of: 12 sides
Find the number of sides in a regular polygon, when each interior angle is: 135°
Find the number of sides in a regular polygon, when each exterior angle is: 72°
The angles of a pentagon are 100°, 96°, 74°, 2x° and 3x°. Find the measures of the two angles 2x° and 3x°.
Calculate the measure of each angle of a regular polygon of 20 sides.
Is it possible to have a polygon whose each interior angle is 105°?
The ratio between the number of sides of two regular polygon is 3 : 4 and the ratio between their interior angles is 2 : 3. Find the number of sides of each polygon.
The exterior angle of a regular polygon is one-third of its interior angle. Find the number of sides of the polygon.
