Advertisements
Advertisements
Question
Find the sum of the interior angles of a polygon of: 12 sides
Solution
When n = 12
∴ Sum of interior angles
= (n - 2) x 180°
= (12 - 2) x 180°
= 10 x 180°
= 1800°.
APPEARS IN
RELATED QUESTIONS
In a pentagon ABCDE, AB is parallel to DC and ∠A: ∠E : ∠D = 3: 4: 5. Find angle E.
Find each exterior angle of a regular polygon of: 9 sides
Find each exterior angle of a regular polygon of: 18 sides
The angles of a pentagon are 100°, 96°, 74°, 2x° and 3x°. Find the measures of the two angles 2x° and 3x°.
Is it possible to have a polygon whose sum of interior angles is 780°?
The ratio between the number of sides of two regular polygon is 3 : 4 and the ratio between their interior angles is 2 : 3. Find the number of sides of each polygon.
The difference between an exterior angle of (n - 1) sided regular polygon and an exterior angle of (n + 2) sided regular polygon is 6°. Find the value of n.
In a hexagon JKLMNO, side JK || ON and ∠K : ∠L : ∠M : ∠N = 6 : 5 : 4 : 3. Find the angle ∠K and ∠M.
In a regular pentagon PQRST, PR = QT intersect at N. Find the angle RQT and QNP.
Each exterior angle of a regular polygon is `(1)/"P" `times of its interior angle. Find the number of sides in the polygon.