Advertisements
Advertisements
Question
Find the number of sides in a regular polygon, when each exterior angle is: 72°
Solution
Each exterior angle
= `(360°)/"n"`
⇒ `(360°)/"n"` = 72°
⇒ n = 5.
APPEARS IN
RELATED QUESTIONS
The sum of the interior angles of a polygon is four times the sum of its exterior angles.
Find the number of sides in the polygon.
The ratio between an exterior angle and an interior angle of a regular polygon is 2 : 3. Find the number of sides in the polygon.
Three angles of a seven-sided polygon are 132o each and the remaining four angles are equal. Find the value of each equal angle.
Find the sum of the interior angles of a polygon of: 7 sides
Find the number of sides in a regular polygon, when each interior angle is: 120°
Find the number of sides in a regular polygon, when each exterior angle is: 20°
Calculate the measure of each angle of a regular polygon of 20 sides.
Is it possible to have a polygon whose each interior angle is 124°?
KL, LM and MN are three consecutive sides of a regular polygon. If ∠LKM = 20°, find the interior angle of the polygon and the number of sides of the polygon.
In a regular pentagon PQRST, PR = QT intersect at N. Find the angle RQT and QNP.
