Advertisements
Advertisements
Question
Three angles of a seven-sided polygon are 132o each and the remaining four angles are equal. Find the value of each equal angle.
Solution
Let the measure of each equal angles are x.
Then we can write:
3 × 132° + 4x = (2 × 7 - 4) 90°
4x = 900° - 396°
4x = 504°
x = `(504°)/4`
x = 126°
Thus the measure of each equal angles are 126°.
APPEARS IN
RELATED QUESTIONS
In a parallelogram ABCD, AB = 20 cm and AD = 12 cm. The bisector of angle A meets DC at E and BC produced at F.
Find the length of CF.
Find the measure of each interior angle of a regular polygon of: 15 sides
The angles of a pentagon are 100°, 96°, 74°, 2x° and 3x°. Find the measures of the two angles 2x° and 3x°.
Is it possible to have a polygon whose sum of interior angles is 7 right angles?
A heptagon has three angles equal to 120°, and the other four angles are equal. Find all the angles.
KL, LM and MN are three consecutive sides of a regular polygon. If ∠LKM = 20°, find the interior angle of the polygon and the number of sides of the polygon.
The ratio between the number of sides of two regular polygon is 3 : 4 and the ratio between their interior angles is 2 : 3. Find the number of sides of each polygon.
Find the value of each angle of an octagon if two of its angles are 148° and 152° and the remaining angles are all equal.
The exterior angle of a regular polygon is one-third of its interior angle. Find the number of sides of the polygon.
In a pentagon PQRST, ∠P = 100°, ∠Q = 120° and ∠S = ∠T. The sides PQ and SR, when produced meet at right angle. Find ∠QRS and ∠PTS.
