Advertisements
Advertisements
Question
In a polygon, there are 5 right angles and the remaining angles are equal to 195o each. Find the number of sides in the polygon.
Solution
Therefore,
Sum of interior angles = (n − 2)180°
Given that there are 5 right angles.
Sum of interior angles = 5 × 90° + (n − 5)195°
⇒ (n − 2)180° = 450° + (n − 5)195°
⇒ 180 n − 360° = 450° + 195 n − 975°
⇒ 195 n − 180 n = 525° − 360°
`=> "n" = (165°)/(15°)`
⇒ n = 11
APPEARS IN
RELATED QUESTIONS
The difference between an exterior angle of (n - 1) sided regular polygon and an exterior angle of (n + 2) sided regular polygon is 6° find the value of n.
Find the measure of each interior angle of a regular polygon of: 15 sides
Find the number of sides in a regular polygon, when each interior angle is: 140°
Find the number of sides in a regular polygon, when each exterior angle is: 72°
The angles of a pentagon are 100°, 96°, 74°, 2x° and 3x°. Find the measures of the two angles 2x° and 3x°.
Is it possible to have a polygon whose sum of interior angles is 7 right angles?
Is it possible to have a polygon whose each interior angle is 105°?
Find the value of each angle of an octagon if four of its angles are equal and the other four are each greater than these by 20°.
The exterior angle of a regular polygon is one-third of its interior angle. Find the number of sides of the polygon.
In a regular pentagon PQRST, PR = QT intersect at N. Find the angle RQT and QNP.
