Advertisements
Advertisements
Question
Find the number of sides in a regular polygon, when each interior angle is: 135°
Solution
Each interior angle of a regular polygon
= `(("n" - 2) xx 180°)/"n"`
⇒ `(("n" - 2) xx 180°)/"n"` = 135°
⇒ 180°(n - 2) = 135°(n)
⇒ 4(n - 2) = 3n
⇒ n = 8.
APPEARS IN
RELATED QUESTIONS
The angles of a pentagon are in the ratio 4: 8: 6: 4: 5.
Find each angle of the pentagon.
The difference between an exterior angle of (n - 1) sided regular polygon and an exterior angle of (n + 2) sided regular polygon is 6° find the value of n.
Three angles of a seven-sided polygon are 132o each and the remaining four angles are equal. Find the value of each equal angle.
Find the measure of each interior angle of a regular polygon of: 10 sides
Find the number of sides in a regular polygon, when each exterior angle is: 60°
The angles of a pentagon are 100°, 96°, 74°, 2x° and 3x°. Find the measures of the two angles 2x° and 3x°.
Is it possible to have a polygon whose sum of interior angles is 7 right angles?
If the difference between an exterior angle of a regular polygon of 'n' sides and an exterior angle of another regular polygon of '(n + 1)' sides is equal to 4°; find the value of 'n'.
KL, LM and MN are three consecutive sides of a regular polygon. If ∠LKM = 20°, find the interior angle of the polygon and the number of sides of the polygon.
Each exterior angle of a regular polygon is `(1)/"P" `times of its interior angle. Find the number of sides in the polygon.
