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प्रश्न
Find the median of 17, 23, 36, 12, 18, 23, 40 and 20
उत्तर
Arranging in ascending order, we get
12, 17, 18, 20, 23, 23, 36, 40
Here, number of terms = 8 which is even
∴ Median = `1/2 {"n"/2 "th term"+("n"/2 + 1)"th"}`
`= 1/2 {8/2"th term" + (8/2 + 1)"th term"}`
`= 1/2 {4 "th term" + 5 "th term"}`
`= 1/2 {20 +23}`
`= 1/2 xx 43 = 21.5`
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संबंधित प्रश्न
The median is always one of the numbers in a data.
The ages of 40 students are given in the following table :
Age (in years) | 12 | 13 | 14 | 15 | 16 | 17 | 18 |
Frequency | 2 | 4 | 6 | 9 | 8 | 7 | 4 |
Find the arithmetic mean.
Find mean by step-deviation method:
C.I. | 63 – 70 | 70 – 77 | 77 – 84 | 84 – 91 | 91 – 98 | 98 – 105 | 105 – 112 |
Frequency | 9 | 13 | 27 | 38 | 32 | 16 | 15 |
The mean of the following distribution is 62.8 and the sum of all the frequencies is 50. Find the missing frequencies f1 and f2.
Class | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 | 80 – 100 | 100 – 120 |
Frequency | 5 | f1 | 10 | f2 | 7 | 8 |
A boy scored following marks in various class tests during a term; each test being marked out of 20.
15, 17, 16, 7, 10, 12, 14, 16, 19, 12 and 16
What are his total marks?
Find the mean of the following frequency distribution :
class | 0-6 | 6-12 | 12-18 | 18-24 | 24-30 |
Frequency | 7 | 5 | 10 | 12 | 6 |
Find the median of the following frequency distribution :
Weight(kg) | 36 | 38 | 40 | 42 | 44 |
No. of students | 11 | 26 | 29 | 24 | 10 |
The mean of marks scored by 100 students was found to be 40, later on, it was discovered that a score of 53 was misread as 83. Find the correct mean.
Find the mean and the median of: 0.5, 5.6, 3.8, 4.9, 2.7 and 4.4
The marks of 200 students in a test were recorded as follows:
Marks % |
0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 | 80-90 | 90-100 |
No. of students |
5 | 7 | 11 | 20 | 40 | 52 | 36 | 15 | 9 | 5 |
Using graph sheet draw ogive for the given data and use it to find the,
- median,
- number of students who obtained more than 65% marks
- number of students who did not pass, if the pass percentage was 35.