Advertisements
Advertisements
प्रश्न
Find the roots of the following quadratic equation by the factorisation method:
`21x^2 - 2x + 1/21 = 0`
उत्तर
Given equation is `21x^2 - 2x + 1/21` = 0
On multiplying by 21 on both sides, we get
441x2 – 42x + 1 = 0
⇒ 441x2 – (21x + 21x) + 1 = 0 ....[By splitting the middle term]
⇒ 44x2 – 21x – 21x + 1 = 0
⇒ 21x(21x – 1) – 1(21x – 1) = 0
⇒ (21x – 1)(21x – 1) = 0
Now, 21x – 1 = 0
⇒ x = `1/21` and 21x – 1 = 0
∴ x = `1/21`
Hence, the roots of the equation 441x2 – 42x + 1 = 0 are `1/21` and `1/21`.
APPEARS IN
संबंधित प्रश्न
Solve for x : `(x+1)/(x-1)+(x-1)/(x+2)=4-(2x+3)/(x-2);x!=1,-2,2`
Solve for x : 12abx2 – (9a2 – 8b2 ) x – 6ab = 0
Solve the following quadratic equations by factorization:
`x^2-(sqrt3+1)x+sqrt3=0`
Some students planned a picnic. The budget for food was Rs. 480. But eight of these failed to go and thus the cost of food for each member increased by Rs. 10. How many students attended the picnic?
In a class test, the sum of the marks obtained by P in Mathematics and science is 28. Had he got 3 marks more in mathematics and 4 marks less in Science. The product of his marks would have been 180. Find his marks in two subjects.
Solve the following quadratic equation by factorisation.
7m2 = 21m
Solve the following quadratic equations by factorization: \[\frac{1}{2a + b + 2x} = \frac{1}{2a} + \frac{1}{b} + \frac{1}{2x}\]
The sum of the squares of three consecutive natural numbers is 110. Determine the numbers.
In each of the following, determine whether the given values are solution of the given equation or not:
x2 - 3`sqrt(3)` + 6 = 0; x = `sqrt(3)`, x = -2`sqrt(3)`
Which of the following are the roots of the quadratic equation, x2 – 9x + 20 = 0 by factorisation?
