Advertisements
Advertisements
प्रश्न
Find the slope of the line passing through the points M(4,0) and N(-2,-3).
उत्तर
`"Slope of a line passing through 2 points "(x_1, "y"_1) " and "(x_1,"y"_1)=(("y"_2-"y"_1)/(x_2-x_1))`
`"Slope of a line passing through 2 points (4,0) and (-2,-3)"=((-3 - 0)/(-2 - 4))=3/2`
APPEARS IN
संबंधित प्रश्न
Find the slope of the line passing through the points A(-2, 1) and B(0, 3).
The line through A(–2, 3) and B(4, b) is perpendicular to the line 2x – 4y = 5. Find the value of b.
(−2, 4), (4, 8), (10, 7) and (11, –5) are the vertices of a quadrilateral. Show that the quadrilateral, obtained on joining the mid-points of its sides, is a parallelogram.
Find the value(s) of k so that PQ will be parallel to RS. Given : P(5, −1), Q(6, 11), R(6, −4k) and S(7, k2)
The line through P(5, 3) intersects y-axis at Q.
- Write the slope of the line.
- Write the equation of the line.
- Find the co-ordinates of Q.
Find the value of p if the lines, whose equations are 2x – y + 5 = 0 and px + 3y = 4 are perpendicular to each other.
Find the slope of the lines passing through the given point.
P (–3, 1) , Q (5, –2)
Find the slope of the lines passing through the given point.
E(–4, –2) , F (6, 3)
Find k, if PQ || RS and P(2, 4), Q (3, 6), R(3, 1), S(5, k).
Find the slope of a line, correct of two decimals, whose inclination is 75°
Find the slope of a line parallel to the given line 5x-y = 10
Find the slope of a line parallel to the given line 5x + 2y = 11
Find the slope of a line passing through the following pair of points
(5pq,p2q) and (5qr,qr2)
Find the slope and the y-intercept of the following line 5x - 2y = 6
Find the slope of the line passing through the points A(4,7) and B(2,3).
Show that the points A(- 2, 5), B(2, – 3) and C(0, 1) are collinear.
The line through P (5, 3) intersects Y axis at Q.
(i) Write the slope of the line.
(ii) Write the equation of the line.
(iii) Find the coordinates of Q.
Determine whether the following points are collinear. A(–1, –1), B(0, 1), C(1, 3)
Given: Points A(–1, –1), B(0, 1) and C(1, 3)
Slope of line AB = `(square - square)/(square - square) = square/square` = 2
Slope of line BC = `(square - square)/(square - square) = square/square` = 2
Slope of line AB = Slope of line BC and B is the common point.
∴ Points A, B and C are collinear.