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Find the term independent of x in the expansion of (x-2x2)15 - Business Mathematics and Statistics

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प्रश्न

Find the term independent of x in the expansion of

`(x - 2/x^2)^15`

बेरीज

उत्तर

`(x - 2/x^2)^15 = (x + (-2)/x^2)^15` compare with the (x + a)

Here x is x, a is `(-2)/x^2`, n = 15

Let the independent term of x occurs in the general term

`"t"_(r+1) = n"C"_r  x^(n-r) a^r`

`"t"_(r+1) = 15"C"_r  x^(15-r)((-2)/x^2)^r = 15"C"_r  x^(15-r) (-2)^r/(x^2)^r`

`= 15"C"_r  x^(15-r) (-2)^r/(x^(2r))`

`= 15"C"_r  x^(15-r) * x^(-2r) (-2)^r = 15"C"_r  x^(15-r-2r) * (-2)^r`

`= 15"C"_r  x^(15-3r) * (-2)^r`

Independent term occurs only when x power is zero.

15 – 3r = 0

15 = 3r

r = 5

Using r = 5 in (1) we get the independent term

= 15C5 x0 (-2)5 [∵ (-2)5 = (-1)5 25 = -25]

= -32(15C5)

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Binomial Theorem
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पाठ 2: Algebra - Exercise 2.6 [पृष्ठ ४५]

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सामाचीर कलवी Business Mathematics and Statistics [English] Class 11 TN Board
पाठ 2 Algebra
Exercise 2.6 | Q 5. (ii) | पृष्ठ ४५
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