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प्रश्न
Find the value of k and b, if the points P(−3, 1) and Q(2, b) lie on the locus of x2 − 5x + ky = 0
उत्तर
Given P(− 3, 1) lie on x2 – 5x + ky = 0
⇒ (−3)2 – 5(−3) + k(1) = 0
9 + 15 + k = 0
⇒ k = − 24
Q(2, b) lie on x2 – 5x + ky = 0
(2)2 – 5(2) + k(b) = 0
⇒ 4 – 5(2) – 24b = 0
4 − 10 − 24b = 0
⇒ − 24b = 6
⇒ b = `6/(-24) = (1)/4`
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