Advertisements
Advertisements
प्रश्न
Find the value of the angle in the given figure:
उत्तर
In the figure,
∠A + ∠B + ∠C = 180° .....(Sum of angles of a triangle)
⇒ x° + 2x° + 2x° = 180°
⇒ 5x° = 180°
⇒ x° = `(180°)/5=36°`
∴ ∠A = x° = 36°
∠B = 2x° = 2 × 36° = 72°
and ∠C = 2x° = 2 × 36° = 72°
APPEARS IN
संबंधित प्रश्न
The angles of a triangle are arranged in ascending order of magnitude. If the difference
between two consecutive angles is 10°, find the three angles.
AB is a line segment. P and Q are points on opposite sides of AB such that each of them is equidistant from the points A and B (See Fig. 10.26). Show that the line PQ is perpendicular bisector of AB.
Fill in the blank to make the following statement true:
An exterior angle of a triangle is always ......... than either of the interior opposite angles.
The sum of two angles of a triangle is equal to its third angle. Determine the measure of the third angle.
In ΔABC, if bisectors of ∠ABC and ∠ACB intersect at O at angle of 120°, then find the measure of ∠A.
If two sides of a triangle are 5 cm and 1.5 cm, the length of its third side cannot be ______.
Find the unknown marked angles in the given figure:
The length of the sides of the triangle is given. Say what types of triangles they are 4.3 cm, 4.3 cm, 4.3 cm.
The length of the three segments is given for constructing a triangle. Say whether a triangle with these sides can be drawn. Give the reason for your answer.
12 cm, 12 cm, 16 cm
Draw a rough sketch of a triangle ABC. Mark a point P in its interior and a point Q in its exterior. Is point A in its exterior or in its interior?
