Advertisements
Advertisements
प्रश्न
The sum of two angles of a triangle is equal to its third angle. Determine the measure of the third angle.
उत्तर
In the given problem, the sum of two angles of a triangle is equal to its third angle.
We need to find the measure of the third angle.
Thus, it is given, in ΔABC
A+B+C ........(1)
Now, according to the angle sum property of the triangle, we get,
∠A +∠B + ∠C = 180°
∠C + ∠C = 180° (Using 1)
2∠C = 180°
`∠C = (180°)/2`
∠C = 90°
Therefore, the measure of the third angle is
∠C = 90°.
APPEARS IN
संबंधित प्रश्न
Is the following statement true and false :
Sum of the three angles of a triangle is 180 .
In a Δ ABC, the internal bisectors of ∠B and ∠C meet at P and the external bisectors of ∠B and ∠C meet at Q, Prove that ∠BPC + ∠BQC = 180°.
State exterior angle theorem.
If the side BC of ΔABC is produced on both sides, then write the difference between the sum of the exterior angles so formed and ∠A.
In a triangle, an exterior angle at a vertex is 95° and its one of the interior opposite angle is 55°, then the measure of the other interior angle is
Calculate the angles of a triangle if they are in the ratio 4: 5: 6.
Classify the following triangle according to sides:
Classify the following triangle according to angle:
Bisectors of the angles B and C of an isosceles triangle with AB = AC intersect each other at O. BO is produced to a point M. Prove that ∠MOC = ∠ABC.
Can we have two acute angles whose sum is a straight angle? Why or why not?