Advertisements
Advertisements
प्रश्न
Find the value of a line perpendicular to the given line 2x-3y = 4
उत्तर
When the lines are perpendicular to the product of their slopes is -1
i.e m1 x m2 = -1
2x - 3y = 4
3y = 2x -4
y = `2/3"x" -4/3`
Slope m1 = `2/3`
Required slope of line (m2)
m1 - m2 = -1
⇒ m2 = `(-1)/"m"_1`
⇒ m2 = `(-1)/(2//3) = -3/2`
APPEARS IN
संबंधित प्रश्न
In the following diagram, write down:
- the co-ordinates of the points A, B and C.
- the equation of the line through A and parallel to BC.
Point P divides the line segment joining the points A(8, 0) and B(16, –8) in the ratio 3 : 5. Find its co-ordinates of point P. Also, find the equation of the line through P and parallel to 3x + 5y = 7.
Given a straight line x cos 30° + y sin 30° = 2. Determine the equation of the other line which is parallel to it and passes through (4, 3).
Find the value of k such that the line (k – 2)x + (k + 3)y – 5 = 0 is:
- perpendicular to the line 2x – y + 7 = 0
- parallel to it.
From the given figure, find:
- the co-ordinates of A, B and C.
- the equation of the line through A and parallel to BC.
ABCD is a parallelogram where A(x, y), B(5, 8), C(4, 7) and D(2, −4). Find:
- co-ordinates of A.
- equation of diagonal BD.
Find the slope of a line perpendicular to the foloowing line `"x"/2 + "y"/3 = 4/3`
Find the slope of a line perpendicular to the foloowing line 3x - 5y = 9
Find the slope of a line perpendicular to the foloowing line 4x + y = 7
Find the value of a line perpendicular to the given line 3x+4y = 13
