Advertisements
Advertisements
प्रश्न
Find the slope of a line perpendicular to the foloowing line 3x - 5y = 9
उत्तर
When two lines are perpendicular to each other the product of their slope is -1.
i.e m1 x m2 = -1
3x - 5y = 9
y = `3/5"x" - 9/5`
m1 = `3/5`
Slope of required line (m2) = `(-1)/"m"_1 = (-5)/3`
APPEARS IN
संबंधित प्रश्न
A(1, −5), B(2, 2) and C(−2, 4) are the vertices of triangle ABC. Find the equation of the median of the triangle through A.
Point P divides the line segment joining the points A(8, 0) and B(16, –8) in the ratio 3 : 5. Find its co-ordinates of point P. Also, find the equation of the line through P and parallel to 3x + 5y = 7.
Find the value of k such that the line (k – 2)x + (k + 3)y – 5 = 0 is:
- perpendicular to the line 2x – y + 7 = 0
- parallel to it.
A(8, −6), B(−4, 2) and C(0, −10) are vertices of a triangle ABC. If P is the mid-point of AB and Q is the mid-point of AC, use co-ordinate geometry to show that PQ is parallel to BC. Give a special name to quadrilateral PBCQ.
Find the slope of a line perpendicular to the foloowing line `"x"/2 + "y"/3 = 4/3`
Find the slope of a line perpendicular to the foloowing line x - `(3"y")/2 + 1 = 0`
Find the slope of a line perpendicular to the foloowing line 4x + y = 7
Find the value of a line perpendicular to the given line 3x+4y = 13
Find the equation of a line perpendicular to the join of A(3,5) and B(-1,7) if it passes through the midpoint of AB.
Find the equation of a line passing through the intersection of `"x"/10 + "y"/5` = 14 and `"x"/8 + "y"/6` = 15 and perpendicular to the line x - 2y = 5
