Advertisements
Advertisements
प्रश्न
Find the value of a line perpendicular to the given line 3x+4y = 13
उत्तर
When the lines are perpendicular to the product of their slopes is -1
i.e m1 x m2 = -1
3x + 4y = 13
4y = -3x + 13
y = `(-3)/4"x" + 13/4`
m1 = `(-3)/4`
REquired slope = `(-1)/"m"_1 = 4/3`
APPEARS IN
संबंधित प्रश्न
Find the equation of the line passing through (−5, 7) and parallel to x-axis
Find the equation of the line passing through (−5, 7) and parallel to y-axis
A(1, −5), B(2, 2) and C(−2, 4) are the vertices of triangle ABC. Find the equation of the median of the triangle through A.
A(1, −5), B(2, 2) and C(−2, 4) are the vertices of triangle ABC. Find the equation of the altitude of the triangle through B.
Given a straight line x cos 30° + y sin 30° = 2. Determine the equation of the other line which is parallel to it and passes through (4, 3).
From the given figure, find:
- the co-ordinates of A, B and C.
- the equation of the line through A and parallel to BC.
ABCD is a parallelogram where A(x, y), B(5, 8), C(4, 7) and D(2, −4). Find:
- co-ordinates of A.
- equation of diagonal BD.
Find the value of a line perpendicular to the given line 2x-3y = 4
Find the value of a line perpendicular to the given line 9x-3y = 5
Find the relation connecting p and q, if the lines py = 2x + 5 and qx + 3y = 2 are parallel to each other.
