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प्रश्न
Find the value of a line perpendicular to the given line 3x+4y = 13
उत्तर
When the lines are perpendicular to the product of their slopes is -1
i.e m1 x m2 = -1
3x + 4y = 13
4y = -3x + 13
y = `(-3)/4"x" + 13/4`
m1 = `(-3)/4`
REquired slope = `(-1)/"m"_1 = 4/3`
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