Advertisements
Advertisements
प्रश्न
Find the equation of the line parallel to the line 3x + 2y = 8 and passing through the point (0, 1).
उत्तर
3x + 2y = 8
2y = −3x + 8
`y = -3/2x + 8/2`
Slope of given line = `-3/2`
Since the required line is parallel to given straight line.
∴ Slope of required line (m) = `-3/2`
Now the equation of the required line is given by:
y – y1 = m(x – x1)
`=> y - 1 = -3/2 (x - 0)`
`=>` 2y – 2 = −3x
`=>` 3x + 2y = 2
APPEARS IN
संबंधित प्रश्न
Find the equation of the line passing through (−5, 7) and parallel to x-axis
In the following diagram, write down:
- the co-ordinates of the points A, B and C.
- the equation of the line through A and parallel to BC.
A(1, −5), B(2, 2) and C(−2, 4) are the vertices of triangle ABC. Find the equation of the line through C and parallel to AB.
Given a straight line x cos 30° + y sin 30° = 2. Determine the equation of the other line which is parallel to it and passes through (4, 3).
From the given figure, find:
- the co-ordinates of A, B and C.
- the equation of the line through A and parallel to BC.
ABCD is a parallelogram where A(x, y), B(5, 8), C(4, 7) and D(2, −4). Find:
- co-ordinates of A.
- equation of diagonal BD.
Find the slope of a line perpendicular to the foloowing line 3x - 5y = 9
Find the value of a line perpendicular to the given line 3x+4y = 13
The lines px + 5y + 7 = 0 and 2y = 5x - 6 are perpendicular to ach other. Find p.
The lines 3x - 2y + 4 = 0 and 3x + my + 6 = 0 are parallel to each other . Find m.
