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प्रश्न
Find the equation of the line parallel to the line 3x + 2y = 8 and passing through the point (0, 1).
उत्तर
3x + 2y = 8
2y = −3x + 8
`y = -3/2x + 8/2`
Slope of given line = `-3/2`
Since the required line is parallel to given straight line.
∴ Slope of required line (m) = `-3/2`
Now the equation of the required line is given by:
y – y1 = m(x – x1)
`=> y - 1 = -3/2 (x - 0)`
`=>` 2y – 2 = −3x
`=>` 3x + 2y = 2
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