Advertisements
Advertisements
प्रश्न
A(1, −5), B(2, 2) and C(−2, 4) are the vertices of triangle ABC. Find the equation of the altitude of the triangle through B.
उत्तर
Let BE be the altitude of the triangle through B.
Slope of AC = `(4 + 5)/(-2 - 1) = 9/-3 = -3`
∴ Slope of BE = `(-1)/("slope of AC") = 1/3 `
Equation of altitude BE is
`y - 2 = 1/3 (x - 2)`
3y − 6 = x − 2
3y = x + 4
APPEARS IN
संबंधित प्रश्न
Find the equation of the line passing through (−5, 7) and parallel to y-axis
A(1, −5), B(2, 2) and C(−2, 4) are the vertices of triangle ABC. Find the equation of the median of the triangle through A.
Find the value of k such that the line (k – 2)x + (k + 3)y – 5 = 0 is:
- perpendicular to the line 2x – y + 7 = 0
- parallel to it.
From the given figure, find:
- the co-ordinates of A, B and C.
- the equation of the line through A and parallel to BC.
Find the slope of a line perpendicular to the foloowing line `"x"/2 + "y"/3 = 4/3`
Find the slope of a line perpendicular to the foloowing line 3x - 5y = 9
Find the value of a line perpendicular to the given line 2x-3y = 4
Find the value of a line perpendicular to the given line 3x+4y = 13
The lines px + 5y + 7 = 0 and 2y = 5x - 6 are perpendicular to ach other. Find p.
Find the relation connecting a and b, if the lines ay = 2x + 4 and 4y + bx = 2 are perpendicular to each other.
