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Question
A(1, −5), B(2, 2) and C(−2, 4) are the vertices of triangle ABC. Find the equation of the altitude of the triangle through B.
Solution
Let BE be the altitude of the triangle through B.
Slope of AC = `(4 + 5)/(-2 - 1) = 9/-3 = -3`
∴ Slope of BE = `(-1)/("slope of AC") = 1/3 `
Equation of altitude BE is
`y - 2 = 1/3 (x - 2)`
3y − 6 = x − 2
3y = x + 4
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