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प्रश्न
For the demand function D = 100 – `p^2/2`. Find the elasticity of demand at p = 10 and comment on the results.
उत्तर
Given, demand function is D = 100 – `p^2/2`
∴ `(dD)/(dp) = 0 - (2p)/2 = - p`
`eta = (-p)/D . (dD)/(dp)`
∴ `eta = (-p)/(100 - p^2/2).(-p)`
= `p^2/((200 - p^2)/2)`
∴ `eta = (2p)^2/(200 - p^2)`
When p = 10,
`eta = (2(10)^2)/(200 - (10)^2) = 200/100` = 2
∴ Elasticity of demand at p = 10 is 2
Here, η > 0
∴ The demand is elastic.
संबंधित प्रश्न
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`("d"pi)/("d"x)` = `square`
Since Profit is increasing,
`("d"pi)/("d"x)` > 0
∴ Profit is increasing for `square`
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Then C = standing charges + labour charges + processing charges
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Profit `pi = R - C = square`
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∴ `Q < square`
Hence, profit is increasing for `Q < square`
