Advertisements
Advertisements
प्रश्न
Fourth and seventh terms of a G.P. are `1/18` and `-1/486` respectively. Find the G.P.
उत्तर
Let the first term of the G.P. be a and its common ratio be r.
4th term =`1/18 => ar^3 = 1/18`
7th term =`1/486 => ar^6 = 1/486`
Now, `(ar^6)/(ar^3) = ((-1)/486)/(1/18)`
`=> r^3 = -1/27`
`=> r = -1/3`
`ar^3 = 1/18`
`=> a xx (-1/3)^3 = 1/18`
`=> a =- 27/18 = -3/2`
∴ G.P. = a, ar, ar2, ar3, .......
= `-3/2, -3/2 xx (-1/3), -3/2 xx (-1/3)^2, 1/18, .......`
= `-3/2, 1/2, -1/6,1/18, .......`
APPEARS IN
संबंधित प्रश्न
Which term of the G.P.:
`-10, 5/sqrt(3), -5/6,....` is `-5/72`?
Find the geometric progression with 4th term = 54 and 7th term = 1458.
If for a G.P., pth, qth and rth terms are a, b and c respectively; prove that : (q – r) log a + (r – p) log b + (p – q) log c = 0
Q 6
Find the sum of G.P. :
1 + 3 + 9 + 27 + .......... to 12 terms.
Find the sum of G.P. :
`(x + y)/(x - y) + 1 + (x - y)/(x + y) + ..........` upto n terms.
Find the sum of G.P. :
`sqrt(3) + 1/sqrt(3) + 1/(3sqrt(3)) + ..........` to n terms.
How many terms of the geometric progression 1 + 4 + 16 + 64 + …….. must be added to get sum equal to 5461?
Q 7
Find a G.P. for which the sum of first two terms is – 4 and the fifth term is 4 times the third term.