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Fourth and seventh terms of a G.P. are 118 and -1486 respectively. Find the G.P. - Mathematics

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Question

Fourth and seventh terms of a G.P. are `1/18` and `-1/486` respectively. Find the G.P.

Sum

Solution

Let the first term of the G.P. be a and its common ratio be r.

4th term =`1/18 => ar^3 = 1/18`

7th term =`1/486 => ar^6 = 1/486`

Now, `(ar^6)/(ar^3) = ((-1)/486)/(1/18)`

`=> r^3 = -1/27`

`=> r = -1/3`

`ar^3 = 1/18`

`=> a xx (-1/3)^3 = 1/18`

`=> a =- 27/18 = -3/2`

∴ G.P. = a, ar, ar2, ar3, .......

= `-3/2, -3/2 xx (-1/3), -3/2 xx (-1/3)^2, 1/18, .......`

= `-3/2, 1/2, -1/6,1/18, .......` 

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Simple Applications - Geometric Progression
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Chapter 11: Geometric Progression - Exercise 11 (B) [Page 154]

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Selina Mathematics [English] Class 10 ICSE
Chapter 11 Geometric Progression
Exercise 11 (B) | Q 3 | Page 154
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