Advertisements
Advertisements
Question
If the first and the third terms of a G.P. are 2 and 8 respectively, find its second term.
Solution
Let the first term of the G.P. be a and its common ratio be r.
∴ 1st term = a = 2
And 3rd term = 8 `=>` ar2 = 8
Now, `(ar^2)/a = 8/2`
`=>` r2 = 4
`=>` r = 2
When a = 2 and r = 2
2nd term = ar = 2 × 2 = 4
APPEARS IN
RELATED QUESTIONS
Find the G.P. whose first term is 64 and next term is 32.
The product of 3rd and 8th terms of a G.P. is 243. If its 4th term is 3, find its 7th term.
Find the seventh term from the end of the series :
`sqrt(2), 2, 2sqrt(2), ........., 32.`
Find the third term from the end of the G.P.
`2/27, 2/9, 2/3, .........,162.`
Q 6
If each term of a G.P. is raised to the power x, show that the resulting sequence is also a G.P.
If a, b, c are in G.P. and a, x, b, y, c are in A.P., prove that `a/x + c/y = 2`
Q 6
How many terms of the geometric progression 1 + 4 + 16 + 64 + …….. must be added to get sum equal to 5461?
Q 2
