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Question
Find the seventh term from the end of the series :
`sqrt(2), 2, 2sqrt(2), ........., 32.`
Solution
Given series: `sqrt(2), 2, 2sqrt(2), ........., 32.`
Now, `2/sqrt(2) = (2sqrt(2))/2 = sqrt(2)`
So, the given series is a G.P. with common ratio, r = `sqrt(2)`
Here, last term, l = 32
∴ 7th term from an end = `1/r^6`
= `32/(sqrt(2))^6`
= `32/8`
= 4
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