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प्रश्न
Given 3log x + `1/2`log y = 2, express y in term of x.
उत्तर
3log x + `1/2`log y = 2
⇒ log x3 + log√y = 2
⇒ log x3√y = 2
⇒ x3√y = 102
⇒ √y = `10^2/x^3`
Squaring both sides, we get
y = `10000/x^6`
⇒ y = `10000x^-6`
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संबंधित प्रश्न
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