Advertisements
Advertisements
प्रश्न
If `-(1)/(2)` is a solution of the equation 3x2 + 2kx – 3 = 0, find the value of k.
उत्तर
x = `-(1)/(2)` is a solution of the
3x2 + 2kx – 3 = 0,
Substituting the value of x in the given equation
`3((-1)/2)^2 + 2k((-1)/2) - 3` = 0
`3 xx (1)/(4) - k - 3` = 0
`(3)/(4) - k - 3` = 0
⇒ k = `(3)/(4) - 3`
= `-(9)/(4)`
Hence k = `-(9)/(4)`.
APPEARS IN
संबंधित प्रश्न
In the following, determine whether the given values are solutions of the given equation or not:
a2x2 - 3abx + 2b2 = 0, `x=a/b`, `x=b/a`
Which of the following are quadratic equation in x?
`(x+2)^3=x^3-8`
`6x^2+x--12=0`
`(x-1)/(x-2)+(x-3)/(x-4)=3 1/3,x≠2,4`
`4^((x+1))+4^((1-x))=10`
The length of a hall is 5 m more than the breadth. If the area of the floor of the hall is 84m2, find the length and breadth of the hall.
For what values of k does the quadratic equation 4x2 − 12x − k = 0 has no real roots?
Check whether the following are quadratic equations: `x^2 + (1)/(x^2) = 3, x ≠ 0`
Solve the following equation by using quadratic formula and give your answer correct to 2 decimal places : `2x - (1)/x = 1`
The cubic equation has degree:
