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Question
If `-(1)/(2)` is a solution of the equation 3x2 + 2kx – 3 = 0, find the value of k.
Solution
x = `-(1)/(2)` is a solution of the
3x2 + 2kx – 3 = 0,
Substituting the value of x in the given equation
`3((-1)/2)^2 + 2k((-1)/2) - 3` = 0
`3 xx (1)/(4) - k - 3` = 0
`(3)/(4) - k - 3` = 0
⇒ k = `(3)/(4) - 3`
= `-(9)/(4)`
Hence k = `-(9)/(4)`.
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