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प्रश्न
If `f(x) = (24^x - 8^x - 3^x + 1)/(12^x - 4^x - 3^x + 1)` for x ≠ 0
= k, for x = 0
is continuous at x = 0, find k.
उत्तर
Function f is continuous at x = 0
∴ f(0) = `lim_(x→0) "f"(x)`
∴ k = `lim_(x→0) (24^x - 8^x - 3^x + 1)/(12^x - 4^x - 3^x + 1)`
= `lim_(x→0) (8^x*3^x - 8^x - 3^x + 1)/(4^x*3^x - 4^x - 3^x + 1)`
= `lim_(x→0) (8^x(3^x - 1) -1(3^x - 1))/(4^x(3^x - 1) - 1(3^x - 1))`
= `lim_(x→0) ((3^x - 1)(8^x - 1))/((3^x - 1)(4^x - 1))`
= `lim_(x→0) (8^x - 1)/(4^x - 1) ...[(because x→0"," 3^x → 3^0),(therefore 3^x → 1 therefore 3^x ≠ 1),(therefore 3^x - 1 ≠ 0)]`
= `lim_(x→0) (((8^x - 1)/x)/((4^x - 1)/x))` ...[∵ x → 0, ∴ x ≠ 0]
= `log 8/log 4 ...[because lim_(x→0) (("a"^x - 1)/x) = log"a"]`
= `log(2)^3/log(2)^2`
= `(3log2)/(2log2)`
∴ f(0) = `3/2`
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