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प्रश्न
If log10 8 = 0.90; find the value of : log√32
उत्तर
Given that log108 = 0.90
⇒ log102 x 2 x 2 = 0.90
⇒ log1023 = 0.90
⇒ 3log102 = 0.90
⇒ log102 = `0.90/3`
⇒ log102 = 0.30 ...(1)
log √32
=`log_10(32)^(1/2)`
= `1/2 log_10(32)`
= `1/2 log_10( 2 xx 2 xx 2 xx 2 xx 2 )`
= `1/2 log_10(2^5)`
= `1/2 xx 5log_10 2`
= `1/2 xx 5( 0.30 )` [ from(1) ]
= 5 x 0.15
= 0.75
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